# How do you find the vertex and intercepts for #y=x^2-6x+15#?

##### 1 Answer

Mar 29, 2018

Vertex (3, 6)

No x-intercepts.

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex:

Vertex (3, 6)

To find the x-intercepts, make y = 0, and solve the quadratic equation by the improved quadratic formula.

There are no x-intercepts (no real roots). The upward parabola

doesn't intersect the x-axis. It is completely above the x-axis.