Question

If y=15 when x=-2, how do you find y when x=3 given y varies inversely as x?

Answer 1

`y=(-30)/x`

Explanation:

Set `y=kxx1/x " "->" "y=k/x`

Initial condition: `15=k/(-2)`

Multiply both sides by `(-2)`

`k=-30` giving:

`y=(-30)/x`