# If y varies inversely as x, how do you find the constant of variation and the inverse variation equation given y=90 when x =6?

$y = \frac{540}{x} \mathmr{and} x = \frac{540}{y}$.
$y = \frac{k}{x}$, where k is the constant ox proportionality.
In this unique relation, the function ${y}^{- 1}$ is same as the function y.