Question

In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

Answer 1

`8"g"O_2`

Explanation:

The reaction (more visibly) is

`2Al"(s)" + 3/2O_2"(g)" rarr Al_2O_3"(s)"`

To solve this problem, we'll need to convert from mass to moles the `Al`, then use the stoichiometric relationships (the coefficients) to find the moles of `O_2`, then use oxygen's molar mass to find the mass of `O_2` required:

`9cancel("g"Al)((1cancel("mol"Al))/(26.98cancel("g"Al)))((3/2cancel("mol"O_2))/(2cancel("mol"Al)))((32.00"g"O_2)/(1cancel("mol"O_2))) = color(red)(8"g"O_2)`