# In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

May 22, 2017

$8 \text{g} {O}_{2}$

#### Explanation:

The reaction (more visibly) is

$2 A l \text{(s)" + 3/2O_2"(g)" rarr Al_2O_3"(s)}$

To solve this problem, we'll need to convert from mass to moles the $A l$, then use the stoichiometric relationships (the coefficients) to find the moles of ${O}_{2}$, then use oxygen's molar mass to find the mass of ${O}_{2}$ required:

$9 \cancel{\text{g"Al)((1cancel("mol"Al))/(26.98cancel("g"Al)))((3/2cancel("mol"O_2))/(2cancel("mol"Al)))((32.00"g"O_2)/(1cancel("mol"O_2))) = color(red)(8"g} {O}_{2}}$