In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

1 Answer
May 22, 2017

Answer:

#8"g"O_2#

Explanation:

The reaction (more visibly) is

#2Al"(s)" + 3/2O_2"(g)" rarr Al_2O_3"(s)"#

To solve this problem, we'll need to convert from mass to moles the #Al#, then use the stoichiometric relationships (the coefficients) to find the moles of #O_2#, then use oxygen's molar mass to find the mass of #O_2# required:

#9cancel("g"Al)((1cancel("mol"Al))/(26.98cancel("g"Al)))((3/2cancel("mol"O_2))/(2cancel("mol"Al)))((32.00"g"O_2)/(1cancel("mol"O_2))) = color(red)(8"g"O_2)#