In this reaction 2Al+3/2O2 formed Al2O3 ,9 gm of Al will react with how many gm of O2?

1 Answer
May 22, 2017

8"g"O_2

Explanation:

The reaction (more visibly) is

2Al"(s)" + 3/2O_2"(g)" rarr Al_2O_3"(s)"

To solve this problem, we'll need to convert from mass to moles the Al, then use the stoichiometric relationships (the coefficients) to find the moles of O_2, then use oxygen's molar mass to find the mass of O_2 required:

9cancel("g"Al)((1cancel("mol"Al))/(26.98cancel("g"Al)))((3/2cancel("mol"O_2))/(2cancel("mol"Al)))((32.00"g"O_2)/(1cancel("mol"O_2))) = color(red)(8"g"O_2)