Question

In triangle ABC, a=12.2, B=14.0, <A=43° how do you find <B?

Answer 1

Solve triangle, knowing A = 43, a = 12.2, b = 14

Anser: B = 51.30

Explanation:

Apply the trig identity: `sin a/A = sin B/b`
Find angle B:
`sin B/b = sin A/a --> sin B = (14(0.68))/12.2 =`=.78 -->

-->`B = 51.30` deg