# Is c= e/-4  a direct variation, inverse variation, or neither?

Mar 18, 2018

See Below.

#### Explanation:

I'm considering $e$ as a variable.

As We have $c = \frac{e}{-} 4$,

We can Write this as

$\frac{c}{e} = - \frac{1}{4}$ [Dividing both sides by $e$]

As $\frac{c}{e}$ is equal to a constant, we can say $c \propto e$ or, $c$ and $e$ are in

But, This results in a confusing situation.

If we take $c = 1$, we get, $e = - 4.$

But if we put $c = 2$, we get, $e = - 8$.

So, Actually, If we increase $c$, e is decreasing, and again, with the same ratio, $- \frac{1}{4}$.

So, Defintion of Variation and The Results we are getting are contradicting each other.

But still, The graph of the relation shows it is direct.

graph{y = (x/(-4)) [-10, 10, -5, 5]}

I don't think this is a variation. But This is my opinion. I need consultations.

Mar 18, 2018

$e$ is a constant $e \approx 2.71828 \ldots . \to 2.72$ to 2 decimal places
Thus $\frac{e}{- 4}$ is also a constant