# Is it possible to factor y=2x^2-10x+12 ? If so, what are the factors?

Feb 18, 2016

2(x-2)(x-3)

#### Explanation:

first step is to remove the 'common factor'

$2 \left({x}^{2} - 5 x + 6\right)$
now to factor the quadratic , require factors of 6 which sum to -5. These are -2 and -3.

hence $2 {x}^{2} - 10 x + 12 = 2 \left(x - 2\right) \left(x - 3\right)$