# Is it possible to factor y=2x^2-16x+32 ? If so, what are the factors?

Apr 15, 2018

$x = 4$

#### Explanation:

$y = 2 {x}^{2} - 16 x + 32$

$y = 2 \left({x}^{2} - 8 x + 16\right)$

$y = 2 {\left(x - 4\right)}^{2}$

Therefore, the factor is $x = 4$. Note that this is a double root