Question

Is it possible to factor `y=2x^2+4x+8`? If so, what are the factors?

Answer 1

Yes it is possible to factorise `2x^2+4x+8`
The factors are 2,`(x+1-i sqrt(3))`,`(x+1+i sqrt(3))`

Explanation:

`2x^2+4x+8` =2(`x^2+2x+4`)

`x^2+2x+4`=`(x+1-i sqrt(3))` `(x+1+i sqrt(3))`