# Is it possible to factor #y=4x^3-13x-6 #? If so, what are the factors?

##### 1 Answer

Mar 14, 2016

#### Explanation:

Since there is nothing obvious to factor out at the beginning, start by plugging in small numbers for

Plugging in

Now divide

#(4x^3-13x-6)/(x-2)=4x^2+8x+3#

So, from here we know that

#4x^3-13x-6=(x-2)(4x^2+8x+3)#

So now all we need to do is factor

#4x^2+8x+3#

#=4x^2+2x+6x+3#

#=2x(2x+1)+3(2x+1)#

#=(2x+3)(2x+1)#

Thus,

#4x^3-13x-6=(x-2)(2x+3)(2x+1)#