# Is it possible to factor y=6x^2+17x+12 ? If so, what are the factors?

$y = \left(2 x + 3\right) \left(3 x + 4\right)$

#### Explanation:

$6 {x}^{2} + 17 x + 12$
$= 6 {x}^{2} + 9 x + 8 x + 12$
$= 3 x \left(2 x + 3\right) + 4 \left(2 x + 3\right)$
$= \left(2 x + 3\right) \left(3 x + 4\right)$
$\setminus \therefore y = \left(2 x + 3\right) \left(3 x + 4\right)$