# Is it possible to factor y=6x^2+17x+12 ? If so, what are the factors?

##### 1 Answer

$y = \left(2 x + 3\right) \left(3 x + 4\right)$

#### Explanation:

Given quadratic polynomial:

$6 {x}^{2} + 17 x + 12$

$= 6 {x}^{2} + 9 x + 8 x + 12$

$= 3 x \left(2 x + 3\right) + 4 \left(2 x + 3\right)$

$= \left(2 x + 3\right) \left(3 x + 4\right)$

$\setminus \therefore y = \left(2 x + 3\right) \left(3 x + 4\right)$