Is it possible to factor #y=6x^2+7x-20 #? If so, what are the factors?

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Answer 1 · 2015-12-12T22:28:22

Yes, by the grouping method ...

Rewrite the middle term as ...

#y=6x^2 + 15x - 8x - 20#

[Note: #15xx-8=6xx-20#]

Now, use grouping ...

#y=(6x^2 + 15x) -(8x + 20)#

#y=(3x)(2x+5)-4(2x+5)#

#y=(3x-4)(2x+5)#

hope that helped