# Is it possible to factor y=9x^2-48x+64? If so, what are the factors?

Aug 25, 2016

Yes

#### Explanation:

If you are having a problem factorising a quadratic by inspection then use the formula
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

In this example the discriminant ${b}^{2} - 4 a c$=0
So the factors are the same
$x = \frac{48}{2 \cdot 9} = \frac{8}{3}$
So the two factors are both $3 x - 8$