Question

Is it possible to factor `y=9x^2-48x+64`? If so, what are the factors?

Answer 1

Yes

Explanation:

If you are having a problem factorising a quadratic by inspection then use the formula
`x=(-b+-sqrt(b^2-4ac))/(2a)`

In this example the discriminant `b^2-4ac`=0
So the factors are the same
`x=48/(2*9)=8/3`
So the two factors are both `3x-8`