Is it possible to factor #y= x^2 + 5x + 6 #? If so, what are the factors?

Question

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Answer 1 · 2018-03-18T18:59:10

Yes;

Question

y = #x^2# + 5x + 6

Work

The factors of 6 are:
1 and 6
2 and 3
3 and 2
6 and 1
1 and -6
2 and -3
and so on...

Now, which one adds up to the "5x"? Or which one adds up to 5?

The only one that does is:
2 and 3.

So you put everything together:
(x + 2) ( x + 3)

Double-check

#(x + 2) ( x + 3)#

#x^2+ 2x + 3x + 6#

#x^2 + 5x + 6#

Hope this helps!! :)