# Is it possible to factor #y=x^2+x-12 #? If so, what are the factors?

##### 2 Answers

#### Answer:

#### Explanation:

Yes,

In fact, a quadratic polynomial like

In our case, we are having,

Its factors are

and, #beta=(-b-sqrtDelta0/(2a)=(-1-7)/2=-8/2=-4.

Hence the factors are

Another Method, is, as follows :-

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#### Answer:

#### Explanation:

Find two factors of 12 which differ (because of the MINUS 12) by 1, as indicated by the coefficient of the x term.

With a basic knowledge of the times tables we find:

These then are the factors we need. The MINUS 12 also indicates that the sign will be different, (neg x pos = neg)