Is it possible to factor #y=x^2+x-12 #? If so, what are the factors?
In fact, a quadratic polynomial like
In our case, we are having,
Its factors are
Hence the factors are
Another Method, is, as follows :-
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Find two factors of 12 which differ (because of the MINUS 12) by 1, as indicated by the coefficient of the x term.
With a basic knowledge of the times tables we find:
These then are the factors we need. The MINUS 12 also indicates that the sign will be different, (neg x pos = neg)