# Is the following molecule chiral: (CH3)3CCH(CH3)2?

${\left({H}_{3} C\right)}_{3} \stackrel{a}{C} - \stackrel{b}{C} H {\left(C {H}_{3}\right)}_{2}$...THERE is no carbon centre that bears FOUR different substituents of the form $C {R}_{1} {R}_{2} {R}_{3} {R}_{4}$. $\stackrel{a}{C}$ bears three methyl groups, and $\stackrel{b}{C}$ bears TWO methyl groups.