# Is x^2 – 14x + 49 a perfect square trinomial and how do you factor it?

Since $49 = {\left(\pm 7\right)}^{2}$
$2 \times \left(- 7\right) = - 14$
${x}^{2} - 14 x + 49$
$\textcolor{w h i t e}{\text{XXXX}}$$= {\left(x - 7\right)}^{2}$
$\textcolor{w h i t e}{\text{XXXX}}$${x}^{2} - 14 x + 49$ is a perfect square.