# Magnesium will burn in oxygen to form magnesium oxide as represented by the following equation 2Mg(s) + O2(g) -> 2MgO(s) What mass of magnesium will react with 498.1 ml of oxygen at 145.2 degrees Celsius and 0.927 atm?

May 20, 2017

Approx. $300 \cdot m g$

#### Explanation:

We use the Ideal Gas Equation to access the molar quantity of dioxygen gas............

$n = \frac{P V}{R T} = \frac{0.927 \cdot a t m \times 0.4981 \cdot L}{0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 418.4 \cdot K} = 1.34 \times {10}^{-} 2 \cdot m o l$.

Given the stoichiometric equation..........

$M g \left(s\right) + {O}_{2} \left(g\right) \rightarrow M g O \left(s\right)$

There are 1.34xx10^-2*molxx24.31*g*mol^-1=??*g metal required for stoichiometric equivalence.