# Phosphoric acid is commonly supplied as an 85% solution. What mass of this solution would be required to prepare 600.0 mL of a 2.80 M phosphoric acid solution?

0.6000 L dil. acid × $\left({\text{2.80 mol H"_3"PO"_4)/"1 L dil. acid" × ("98.00 g H"_3"PO"_4)/("1 mol H"_3"PO}}_{4}\right)$ ×
("100 g 85 % H"_3"PO"_4)/("85 g H"_3"PO"_4) = "194 g of 85 % H"_3"PO"_4