# Sketch 4,6-diethyl-5-propylnonane and sketch 2,cyclopropylpropane?

Nov 18, 2017

Just to retire this question, you draw the 9-membered carbon backbone first....

#### Explanation:

${H}_{3} C - C {H}_{2} C {H}_{2} C {H}_{2} C {H}_{2} C {H}_{2} C {H}_{2} C {H}_{2} C {H}_{3}$

And then you number the chain appropriately....

${H}_{3} C - \stackrel{2}{C} {H}_{2} C {H}_{2} \stackrel{4}{C} {H}_{2} \stackrel{5}{C} {H}_{2} \stackrel{6}{C} {H}_{2} C {H}_{2} C {H}_{2} C {H}_{3}$

And then you substitute the indicated carbons with the required substituent..

${H}_{3} C - \stackrel{2}{C} {H}_{2} C {H}_{2} \stackrel{4}{C} H {R}_{1} \stackrel{5}{C} H {R}_{2} \stackrel{6}{C} H {R}_{1} C {H}_{2} C {H}_{2} C {H}_{3}$

Where ${R}_{1} = C {H}_{2} C {H}_{3}$, and ${R}_{2} = C {H}_{2} C {H}_{2} C {H}_{3}$.

The three-membered ring is also easy to do; on paper but not on this editor......