# Suppose y varies inversely as x and y=24 when x= 3, how do you find x when y = 36?

Mar 30, 2016

$y = \frac{1}{x}$

$y = k \frac{1}{x}$

$24 = k \frac{1}{3}$

$72 = k$

$y = 72 \frac{1}{x}$

$36 = 72 \frac{1}{x}$

$0.5 = \frac{1}{x}$

$0.5 x = 1$

$x = 2$