# The bases on a playground baseball diamond form a square, 60ft on a side. How far would a catcher standing n home plate need to throw the ball to get a runner out at second base?

Jul 13, 2016

$84.85 f e e t$

#### Explanation:

The line from home plate to second base forms the hypotenuse of right triangle. The two sides of the triangle are each $60 f e e t$. Using the Pythagorean theorem, we can find the length of the hypotenuse:

${60}^{2} + {60}^{2} = {c}^{2}$

= $3600 + 3600 = {c}^{2}$

= $7200 = {c}^{2}$

$\sqrt{7200} = 84.85$

Therefore, the distance that the catcher will need to throw the ball to get a runner out at second base is $84.85 f e e t$.