The combustion of butane, #C_4H_10#, produces carbon dioxide water. When one sample of butane was burned, 4.46 grams of water was formed. How many grams of oxygen gas were consumed?

1 Answer

Answer:

#"10.3 g O"_2#

Explanation:

Combustion reactions with hydrocarbons (compounds made up of only carbon and hydrogen, #C_4H_10#) involve the hydrocarbon reacting with #O_2# gas to form #H_2O# and #CO_2#

We must first balance the equation, we end up with;

#2C_4H_10 + 13O_2 -> 10H_2O + 8CO_2#

with the balanced equation, most of the work is done. We now simply convert from #H_2O# to #O_2# using the mol to mol ratios.

#H = "1.01 g"#
#O = "16.00 g"#
#H_2O = "18.02 g"#
#O_2 = "32.00 g"#

#"4.46 g H"_2"O" xx("1 mol H"_2"O")/("18.02 g H"_2"O") xx("13 mol O"_2)/("10 mol H"_2"O") xx ("32.0 g O"_2)/("1 mol O"_2) = "10.3 g O"_2" gas"#