# The cube root of x varies inversely as the square of y. If x=27 when y=4 how do you find the value of x when y=6?

$x = \frac{64}{27}$
root(3)x prop 1/y^2 or root(3)x = k* 1/y^2 ;x=27 ,y=4 :. root(3) 27 = k/4^2 or 3 =k/16 or k=48 .
So the equation is root(3)x = 48* 1/y^2 ; y=6 ; x= ? root(3)x = 48* 1/6^2= 4/3 :. x =(4/3)^3=64/27 [Ans]