The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #220 ^o K#. If the temperature of the gas changes to #20 ^oC# with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Feb 26, 2016

Answer:

#19.9875 Pa#

Explanation:

As there is no change in Volume #V#, #P/T# is always constant, where #P# is Pressure and #T# is Temperature in degree Kelvin.

As initially container exerts #15Pa# of pressure and is at a temperature of #220^oK#, #P/T=15/220#.

As temperature of the container changes to #20^oC# i.e. #(20+273.15)^oK# i.e. #293.15^oK#, if Pressure changes to #P_1#

#P_1/293.15=15/220#

Hence #T_1=(15xx293.15)/220=19.9875 Pa#