# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 220 ^o K. If the temperature of the gas changes to 20 ^oC with no change in the container's volume, what is the new pressure of the gas?

Feb 26, 2016

$19.9875 P a$

#### Explanation:

As there is no change in Volume $V$, $\frac{P}{T}$ is always constant, where $P$ is Pressure and $T$ is Temperature in degree Kelvin.

As initially container exerts $15 P a$ of pressure and is at a temperature of ${220}^{o} K$, $\frac{P}{T} = \frac{15}{220}$.

As temperature of the container changes to ${20}^{o} C$ i.e. ${\left(20 + 273.15\right)}^{o} K$ i.e. ${293.15}^{o} K$, if Pressure changes to ${P}_{1}$

${P}_{1} / 293.15 = \frac{15}{220}$

Hence ${T}_{1} = \frac{15 \times 293.15}{220} = 19.9875 P a$