The gas inside of a container exerts 42 Pa of pressure and is at a temperature of 270 ^o K. If the pressure in the container changes to 72 Pa with no change in the container's volume, what is the new temperature of the gas?

Feb 26, 2016

New temperature is ${462.86}^{o} K$

Explanation:

As there is no change in Volume $V$, $\frac{P}{T}$ is always constant, where $p$ is Pressure and $T$ is Temperature in degree Kelvin.

As initially container exerts $42 P a$ of pressure and is at a temperature of ${270}^{o} K$, $\frac{P}{T} = \frac{42}{270}$. As pressure in the container changes to $72 P a$, if Temperature changes to ${T}_{1}$

$\frac{72}{T} _ 1 = \frac{42}{270}$

Hence ${T}_{1} = \frac{72 \cdot 270}{42} = {462.86}^{o} K$