# The length of a rectangle is twice its width. If the perimeter of the rectangle is 42 yd how do you find its area?

Sep 13, 2015

The area of the rectangle is 98.

#### Explanation:

Given the length and width, the perimeter of the rectangle is=$2 \left(l + w\right)$

Length is twice its width so $l = 2 w$

Then-
$2 \left(2 w + w\right) = 42 y d$
$6 w = 42 y d$
$w = \frac{42}{6} = 7$
$l = 2 w = 2 \times 7 = 14$
The area of the rectangle is $= \le n > h \times w i \mathrm{dt} h = 14 \times 7 = 98$