The number of football players is 4 times the number of basketball players, and the number of baseball players is 9 more than basketball players. If the total number of players is 93 and each one plays a single sport, how many are on each team?

2 Answers
Sep 28, 2015

5656 football players
1414 basketball players
2323 baseball players

Explanation:

Define:
color(white)("XXX")f: XXXf:number of football players
color(white)("XXX")b: XXXb:number of basketball players
color(white)("XXX")d: XXXd:number of baseball players

We are told:
[1]color(white)("XXX"color(red)(f=4b)XXXf=4b
[2]color(white)("XXX")color(blue)(d=b+9)XXXd=b+9
[3]color(white)("XXX")f+b+d=93XXXf+b+d=93

Substituting (from [1]) color(red)(4b)4b for color(red)(f)f and (from [2]) color(blue)(b+9)b+9 for color(blue)(d)d in [3]
[4]color(white)("XXX")color(red)(4b)+b+color(blue)(b+9) = 93XXX4b+b+b+9=93

Simplifying
[5]color(white)("XXX")6b+9 = 93XXX6b+9=93
[6]color(white)("XXX")6b=84XXX6b=84
[7]color(white)("XXX")b=14XXXb=14

Substituting 1414 for bb in [2]
[8]color(white)("XXX")d=14+9 = 23XXXd=14+9=23

Substituting 1414 for bb in [1]
[9]color(white)("XXX")f=4*14 = 56XXXf=414=56

Sep 28, 2015

56 football players, 14 basketball players, and 23 baseball players.

Explanation:

Let the number of football players be x
Let the number of basketball players be y
Let the number of baseball players be z

Now rewrite all the sentences in algebraic form in terms of x, y and z. Doing so we get :

x=4yx=4y
z=y+9z=y+9
x+y+z=93x+y+z=93

Now we can substitute both x and z (which we have in terms of y) into the last equation and then solve for y. This yields

4y+y+(y+9)=934y+y+(y+9)=93

therefore 6y=84=>y=14 and so there 14 basketball players.

Now substitute the value of y back into the first 1 equations to determine x and z.
therefore x=4xx14=56 and z=14+9=23
This means there are then 56 football players and 23 baseball players.