# The rate of the following reaction is 0.960 M/s. What is the relative rate of change of each species in the reaction? A + 3B -> 2C

Jan 26, 2018

$A + 3 B \to 2 C$

It’s given that

$\text{0.960 M/s} = - \frac{d \left[A\right]}{\mathrm{dt}} = - \frac{1}{3} \frac{d \left[B\right]}{\mathrm{dt}} = \frac{1}{2} \frac{d \left[C\right]}{\mathrm{dt}}$

So,

$\frac{d \left[A\right]}{\mathrm{dt}} = - \text{0.960 M/s}$

(d[B])/dt = -3 × "0.960 M/s" = -"2.88 M/s"

(d[C])/dt = 2 × "0.960 M/s" = "1.92 M/s"