The standard form of #y = 6(x - 2)^2 - 8#?

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Answer 1 · 2018-03-18T07:35:27

The quadratic in standard form is #y=6x^2-24x+16 #.

To expand from vertex form, simply do the multiplication and simplify:

# y=6color(blue)((x-2)^2)-8 #

# color(white)y=6color(blue)((x-2)(x-2))-8 #

# color(white)y=6color(blue)((x^2-4x+4))-8 #

# color(white)y=6x^2-24x+24-8 #

# color(white)y=6x^2-24x+16 #

That's it. Hope this helped!

The standard form of #y = 6(x - 2)^2 ­- 8#?