# The standard form of y = 6(x - 2)^2 ­- 8?

Mar 18, 2018

The quadratic in standard form is $y = 6 {x}^{2} - 24 x + 16$.

#### Explanation:

To expand from vertex form, simply do the multiplication and simplify:

$y = 6 \textcolor{b l u e}{{\left(x - 2\right)}^{2}} - 8$

$\textcolor{w h i t e}{y} = 6 \textcolor{b l u e}{\left(x - 2\right) \left(x - 2\right)} - 8$

$\textcolor{w h i t e}{y} = 6 \textcolor{b l u e}{\left({x}^{2} - 4 x + 4\right)} - 8$

$\textcolor{w h i t e}{y} = 6 {x}^{2} - 24 x + 24 - 8$

$\textcolor{w h i t e}{y} = 6 {x}^{2} - 24 x + 16$

That's it. Hope this helped!