# The sum of 4 consecutive odd integers is 336, how do you find the largest integer?

Jan 29, 2016

I found $87$

#### Explanation:

Let us call the numbers:
$2 n + 1$
$2 n + 3$
$2 n + 5$
$2 n + 7$
We then can write:
$\left(2 n + 1\right) + \left(2 n + 3\right) + \left(2 n + 5\right) + \left(2 n + 7\right) = 336$

rearranging and solving for $n$:

$8 n + 16 = 336$

$n = \frac{320}{8} = 40$

The largest integer will be:

$2 n + 7 = 87$