The sum of three consecutive odd integers is 231, how do you find the integers?

2 Answers
Mar 5, 2016

Answer:

The integers are #75, 77 # and # 79#

Explanation:

Three consecutive odd integers can be denoted as:
#(x) , (x+2)# and# (x+4)#

The sum #=231#

So,

#x + x+2 + x+4 = 231#

#3x+6 = 231#

#3x = 231-6#

#3x = 225#

#x=225/3#

#color(blue)(x=75#

The integers are as follows:
#x; color(blue)(75#

#x+2; color(blue)(77# and

#x+4;color(blue)( 79#

Mar 5, 2016

Answer:

Numbers are #75#, #77# and #79#.

Explanation:

Let the three odd numbers be #2x-1#, #2x+1# and #2x+3#. (These numbers have been chosen as these will always be three consecutive odd number for any natural number #x#).

As sum of these numbers is #231#

#2x-1+2x+1+2x+3=231# or

#6x+3=231# or #6x=231-3=228#

Hence #6x=228# or #x=228/6=38# and numbers are

#2xx38-1#, #2xx38+1# and #2xx38+3#

or #75#, #77# and #79#.