To what pressure would you have to compress 48.0 L of oxygen gas at 99.3 kPa in order to reduce its volume to 16.0 L?

1 Answer
Aug 11, 2016

Answer:

#298 kPa#

Explanation:

The answer can be determined by using Boyle's Law:
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Let's identify our known and unknown variables.

#color(red)("Knowns:"#
#P_1#= 99.3 kpa
#V_1#= 48.0 L
#V_2#= 16.0 L

#color(maroon)("Unknowns:"#
#P_2#

Rearrange the equation to solve for the final pressure by dividing both sides by #V_2# to get #P_2# by itself like this:

#P_2=(P_1xxV_1)/V_2#

Plug in your given values to obtain the final pressure:

#P_2=(99.3\kPa xx 48.0\ cancel"L")/(16.0\cancel"L")# = #298kPa#