Two consecutive odd integers have a sum of 128, what are the integers?

2 Answers
May 10, 2018

Answer:

#63 " and " 65#

Explanation:

My strategy for doing problems like this is to divide #128# in half, and take the odd integer directly above and below the result. Doing this for #128# yields this:

#128/2=64#

#64-1=63#
#64+1=65#

#63+65=128#

As #63# and #65# are two consecutive odd integers that sum to #128#, this satisfies the problem.

May 10, 2018

Answer:

they are #63# and #65#.

Explanation:

since the two numbers are odd, and consecutive, they have a difference of #2#.
suppose the smaller integer of the two #= x#
#128=x+(x+2)#
#=2x+2#

so as to find the smaller odd integer, you need to find the value of #x#:
#128-2=2x+2-2#
#=126=2x#

#126/2=(2x)/2=63#

#x=63#

63 is the smaller number, so the bigger number is #63+2=65#