Two consecutive odd integers have a sum of 128, what are the integers?

2 Answers
May 10, 2018

63 " and " 65

Explanation:

My strategy for doing problems like this is to divide 128 in half, and take the odd integer directly above and below the result. Doing this for 128 yields this:

128/2=64

64-1=63
64+1=65

63+65=128

As 63 and 65 are two consecutive odd integers that sum to 128, this satisfies the problem.

May 10, 2018

they are 63 and 65.

Explanation:

since the two numbers are odd, and consecutive, they have a difference of 2.
suppose the smaller integer of the two = x
128=x+(x+2)
=2x+2

so as to find the smaller odd integer, you need to find the value of x:
128-2=2x+2-2
=126=2x

126/2=(2x)/2=63

x=63

63 is the smaller number, so the bigger number is 63+2=65