Two corners of a triangle have angles of # (3 pi )/ 8 # and # ( pi ) / 2 #. If one side of the triangle has a length of # 16 #, what is the longest possible perimeter of the triangle?

Question

987 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-08T15:14:44

Largest possible area of the triangle is 309.0193

Given are the two angles #(pi)/2# and #(3pi)/8# and the length 16

The remaining angle:

#= pi - ((pi)/2) + (3pi)/8) = (pi)/8#

I am assuming that length AB (16) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C)#

Area#=( 16^2*sin(pi/2)*sin((3pi)/8))/(2*sin(pi/8))#

Area#=309.0193#