Two corners of a triangle have angles of # (5 pi )/ 8 # and # ( pi ) / 6 #. If one side of the triangle has a length of # 2 #, what is the longest possible perimeter of the triangle?

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Answer 1 · 2017-12-11T07:45:19

Largest possible area of the triangle is **2.2497

Given are the two angles #(5pi)/8# and #pi/6# and the length 7

The remaining angle:

#= pi -( ((5pi)/8) + pi/6) = (5pi)/24#

I am assuming that length AB (2) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C))#

Area#=( 2^2*sin((5pi)/24)*sin((5pi)/8))/(2*sin(pi/6))#

Area#=2.2497#