Question

Two corners of a triangle have angles of `( pi )/ 2` and `( pi ) / 4`. If one side of the triangle has a length of `17`, what is the longest possible perimeter of the triangle?

Answer 1

This is an isosceles right triangle. For the longest perimeter we'll make the short side `17`, so a perimeter of `17+17+17\sqrt{2}=34+17sqrt{2}.`