Two corners of an isosceles triangle are at #(2 ,5 )# and #(9 ,8 )#. If the triangle's area is #6 #, what are the lengths of the triangle's sides?

1 Answer

1.) #sqrt58#,#" " "sqrt58#,#" " "2sqrt(29+sqrt(805))#
2.) #sqrt58=7.615#,#" " "sqrt58=7.615#,#" " "2sqrt(29-sqrt(805))=1.58427#
3.)#sqrt58=7.615#,#sqrt(57130)/58=4.12101#,#sqrt(57130)/58=4.12101#

Explanation:

The possible triangles are when the given distance #sqrt58# are the two equal sides

triangle 1: the coordinates are #(2,5), (9,8), ((279+7sqrt805)/29,(190+3sqrt805)/29)#

triangle 2: the coordinates are #(2, 5), (9, 8), ((279-7sqrt805)/29,(190-3sqrt805)/29)#

For the 3rd triangle, #sqrt58# is the 3rd side and is not congruent to any side.
triangle 3: the coordinates are #(2, 5), (9, 8), (355/58, 293/58)#

God bless....I hope the explanation is useful.