Two rhombuses have sides with lengths of #12 #. If one rhombus has a corner with an angle of #pi/2 # and the other has a corner with an angle of #(3pi)/8 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2016-04-28T17:00:28

The difference in area is #10.96#

Area of a rhombus is given by #s^2sintheta#, where #s# is one of the side and #theta# is the angle between the two sides.

Area of first rhombus is #12xx12xxsin(pi/2)=12xx12xx1=144#

Area of other triangle is #12xx12xxsin(3pi/8)=12xx12xx0.9239=133.04#

The difference in area is #144-133.04=10.96#