Two rhombuses have sides with lengths of 16. If one rhombus has a corner with an angle of π12 and the other has a corner with an angle of 5π6, what is the difference between the areas of the rhombuses?

1 Answer
Mar 20, 2016

Difference between the areas of the rhombuses is 30.848 sq.units.

Explanation:

Area of a parallelogram with sides a and b and included angle θ is given by 12×a×b×sinθ. As it is a rhombus, two sides are equal area will be 12×a2×sinθ.

Hence area of rhombus with side 16 and angle π12 is

12×162×sin(π12)=12×256×0.259=33.152

Hence area of rhombus with side 16 and angle 5π6 is

12×162×sin(5π6)=12×256×0.5=64

Difference between the areas of the rhombuses is 6433.152=30.848