What are the components of the vector between the origin and the polar coordinate $(- 9, \frac{23 π}{12})$ $(-9, (23pi)/12)$ ?

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Answer 1 · 2018-02-27T05:42:25

$V_{x} = - 6.8933, V_{y} = 2.3294, tan (θ) = - 0.2679$ $color(purple)(V_x = -6.8933, V_y = 2.3294, tan (theta) = - 0.2679$

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$r = - 9, θ = \frac{23 π}{12}$ $r = -9, theta = (23pi)/12$

$V_{x} = - 9 \cdot cos (\frac{23 π}{12}) = - 8.6933$ $V_x = -9 * cos ((23pi)/12) = -8.6933$

$V_{y} = - 9 \cdot sin (\frac{23 π}{12}) = 2.3294$ $V_y = -9 * sin ((23pi)/12) = 2.3294$

$tan θ = tan (\frac{23 π}{12}) = - 0.2679$ $tan theta = tan ((23pi)/12) = -0.2679$

What are the components of the vector between the origin and the polar coordinate (-9, (23pi)/12)(−9,23π12)(-9, (23pi)/12)?