What are the components of the vector between the origin and the polar coordinate $(2, \frac{- π}{6})$ $(2, (-pi)/6)$ ?

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What are the components of the vector between the origin and the polar coordinate $(2, \frac{- π}{6})$ $(2, (-pi)/6)$ ?

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Answer 1 · 2016-03-05T16:57:42

$= \sqrt{3} ˆ i - ˆ j$ $=sqrt3hati-hatj$

Explanation:

if $(r, θ)$ $(r,theta)$ be the polar coordinate of position vector $\to a$ $veca$ with respect to the origin then then $\to a = r cos θ ˆ i + r sin θ ˆ j$ $veca= rcosthetahati+rsinthetahatj$
Hence for the coordinate $(2, - \frac{π}{6})$ $(2,-pi/6)$ the vector becomes

$\to a = 2 cos (- \frac{π}{6}) ˆ i + 2 sin (- \frac{π}{6}) ˆ j = \sqrt{3} ˆ i - ˆ j$ $veca=2cos(-pi/6)hati+2sin(-pi/6)hatj=sqrt3hati-hatj$

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What are the components of the vector between the origin and the polar coordinate $(2, \frac{- π}{6})$ $(2, (-pi)/6)$ ?

1 Answer

Explanation:

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What are the components of the vector between the origin and the polar coordinate (2,−π6)(2, (-pi)/6)?

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What are the components of the vector between the origin and the polar coordinate $(2, \frac{- π}{6})$ $(2, (-pi)/6)$ ?