What are the components of the vector between the origin and the polar coordinate $(1, \frac{- 3 π}{4})$ $(1, (-3pi)/4)$ ?

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What are the components of the vector between the origin and the polar coordinate $(1, \frac{- 3 π}{4})$ $(1, (-3pi)/4)$ ?

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Answer 1 · 2016-01-18T01:27:37

The coordinate is on the unit circle ( $r = 1$ $r=1$ ). Specifically, it is at $\frac{- 3 π}{4}$ $(-3pi)/4$ or $- 135^{o}$ $-135^o$ . Now, use a unit circle to identify the x and y coordinates ...

Explanation:

$- 135^{o} = 225^{o}$ $-135^o=225^o$ , so $x = y = \frac{- \sqrt{2}}{2}$ $x=y=(-sqrt2)/2$

Component Vector $= < \frac{- \sqrt{2}}{2}, \frac{- \sqrt{2}}{2} >$ $=<(-sqrt2)/2, (-sqrt2)/2>$

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What are the components of the vector between the origin and the polar coordinate $(1, \frac{- 3 π}{4})$ $(1, (-3pi)/4)$ ?

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Explanation:

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What are the components of the vector between the origin and the polar coordinate $(1, \frac{- 3 π}{4})$ $(1, (-3pi)/4)$ ?