Question

What are the components of the vector between the origin and the polar coordinate `(-1, (-3pi)/4)`?

Answer 1

`x=sqrt2/2`

`y=sqrt2/2`

Explanation:

Given `r=-1` and `theta=(-3pi)/4`

`x=r*cos theta=(-1)*cos ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2`

`y=r*sin theta=(-1)*sin ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2`

God bless....I hope the explanation is useful.