What are the components of the vector between the origin and the polar coordinate $(- 1, \frac{- 3 π}{4})$ $(-1, (-3pi)/4)$ ?

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What are the components of the vector between the origin and the polar coordinate $(- 1, \frac{- 3 π}{4})$ $(-1, (-3pi)/4)$ ?

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Answer 1 · 2016-05-29T11:03:11

$x = \frac{\sqrt{2}}{2}$ $x=sqrt2/2$

$y = \frac{\sqrt{2}}{2}$ $y=sqrt2/2$

Explanation:

Given $r = - 1$ $r=-1$ and $θ = \frac{- 3 π}{4}$ $theta=(-3pi)/4$

$x = r \cdot cos θ = (- 1) \cdot cos (\frac{- 3 π}{4}) = (- 1) (\frac{- 1}{\sqrt{2}}) = \frac{\sqrt{2}}{2}$ $x=r*cos theta=(-1)*cos ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2$

$y = r \cdot sin θ = (- 1) \cdot sin (\frac{- 3 π}{4}) = (- 1) (\frac{- 1}{\sqrt{2}}) = \frac{\sqrt{2}}{2}$ $y=r*sin theta=(-1)*sin ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2$

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What are the components of the vector between the origin and the polar coordinate $(- 1, \frac{- 3 π}{4})$ $(-1, (-3pi)/4)$ ?

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Explanation:

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