What are the components of the vector between the origin and the polar coordinate (5, (-11pi)/6)?

1 Answer
Jan 27, 2018

We can use x=rcos(theta) and y=rsin(theta) to convert to the polar point to rectangular:

x=5cos(-(11pi)/6)=5(sqrt(3)/2)=(5sqrt(3))/2
y=5sin(-(11pi)/6)=5(1/2)=(5)/2

So the rectangular form is ( (5sqrt(3))/2, (5)/2 ).

Since we're talking about the component form of the vector, the initial point is (0,0).

The component form of the vector is [(5sqrt(3))/2, (5)/2 ].