What are the components of the vector between the origin and the polar coordinate (6, (2pi)/3)?

1 Answer
Jul 7, 2016

((-3),(3sqrt3))

Explanation:

To convert from color(blue)"Polar to Cartesian coordinates"

That is (r,theta)to(x,y)

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|)))

here r = 6 and theta=(2pi)/3
color(blue)"-------------------------------------"
rArrx=6cos((2pi)/3)

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(cos((2pi)/3)=-cos(pi-(2pi)/3)=-cos(pi/3))color(white)(a/a)|)))

rArrx=-6cos(pi/3)=-6xx1/2=-3
color(blue)"--------------------------------------------------------------"

and y =6sin((2pi)/3)

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(sin((2pi)/3)=sin(pi-(2pi)/3)=sin(pi/3))color(white)(a/a)|))

rArry=6sin(pi/3)=6xxsqrt3/2=3sqrt3
color(blue)"----------------------------------------------------"

Thus the components of the vector=((-3),(3sqrt3))