What are the components of the vector between the origin and the polar coordinate (6, (2pi)/3)?
1 Answer
Explanation:
To convert from
color(blue)"Polar to Cartesian coordinates" That is
(r,theta)to(x,y)
color(orange)"Reminder"
color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|))) here r = 6 and
theta=(2pi)/3
color(blue)"-------------------------------------"
rArrx=6cos((2pi)/3)
color(orange)"Reminder"
color(red)(|bar(ul(color(white)(a/a)color(black)(cos((2pi)/3)=-cos(pi-(2pi)/3)=-cos(pi/3))color(white)(a/a)|)))
rArrx=-6cos(pi/3)=-6xx1/2=-3
color(blue)"--------------------------------------------------------------" and y
=6sin((2pi)/3)
color(orange)"Reminder"
color(red)(|bar(ul(color(white)(a/a)color(black)(sin((2pi)/3)=sin(pi-(2pi)/3)=sin(pi/3))color(white)(a/a)|))
rArry=6sin(pi/3)=6xxsqrt3/2=3sqrt3
color(blue)"----------------------------------------------------" Thus the components of the vector
=((-3),(3sqrt3))