What are the components of the vector between the origin and the polar coordinate $(3, (13pi)/12)$ ?

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Answer 1 · 2018-03-14T01:50:42

Coordinates are $x = -3.1058, -0.7765$

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Given : $r = 3, theta = (13pi)/12$ since $(13pi)/12$ , the vector is in the third quadrant where x & y are negative as cos & sin are negative.

$x = r cos theta = 3 * cos ((13pi)/12) = 3 * (-cos ((pi)/12))$

$x = - 3.1058$

$y = r * sin theta = 3 * sin ((13pi)/12) = 3 * (-sin (pi/12))$

$y = - 0.7765$

Slope $m = tan theta = y / x =( -0.7765) / ( -3.1058) = 0.25$

What are the components of the vector between the origin and the polar coordinate (3, (13pi)/12)(3, (13pi)/12)?