What are the components of the vector between the origin and the polar coordinate #(-8, (13pi)/12)#?

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Answer 1 · 2017-11-05T11:52:44

#7.727hati+2.071hatj#

First convert the polar coordinate into a Cartesian coordinate. This can be done using:

#x=rcos(theta)#

#y=rsin(theta)#

#:.#

#x= -8(cos((13pi)/12))=7.727# (3 .d.p)

#y=-8(sin((13pi)/12))=2.071# (3 .d.p)

#7.727hati+2.071hatj#