Question

What are the components of the vector between the origin and the polar coordinate `(-1, (7pi)/6)`?

Answer 1

`< sqrt(3)/2, 1/2 >`

Explanation:

`theta = (7pi)/6` would be in Quadrant III
but the negative sign on the radius `(r=-1)` shifts it back through the origin into Quadrant I

Polar coordinate `(-1,(7pi)/6)`
is therefore equivalent to `(1,pi/6)`
which is a standard angle as in the image below: