What are the components of the vector between the origin and the polar coordinate #(9, (17pi)/12)#?

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Answer 1 · 2017-12-03T08:34:45

#-2.33hati-8.69hatj#

First convert the polar coordinate in a Cartesian coordinate. This can be done using:

#x=rcos(theta)#

#y=rsin(theta)#

#x= 9cos((17pi)/12)=-2.33#

#y= 9sin((17pi)/12)=-8.69#

Cartesian coordinates:

#( -2.33 , -8.69 )#

Vector components.

#x=-2.33hati#

#y=-8.69hatj#

#:.#

#-2.33hati-8.69hatj#